What will be the address range of 2048?

What will be the address range of 2048?

So the total number of located memory in the range of address is from C000H to C7FFH which is 7FFH + 1 = 800H i.e. 2048 = 2K. The circuit below gives us information to know the range of ranging from C000H–C7FFH.

How many lines of the address bus must be used to access total memory how many of these lines will be common to all chips?

How many 128 × 8 RAM chips are needed to provide a memory capacity of 2048 bytes? How many lines of the address bus must be used to access 2048 byte of memory?…Subscribe to GO Classes for GATE CSE 2022.

How many 128×8 RAM chips are needed to provide a memory capacity of 2048 bytes?

Since 8 bits = 1 byte, Each RAM chip has 64 x 1 byte = 64 bytes. Thus the number of chips to address a memory capacity of 2048 bytes will be, 2048/64 = 32 chips….Subscribe to GO Classes for GATE CSE 2022.

How many lines of the address must be used to access 512K bytes?

512K/8 = 64K; therefore, the organization for this memory chip is 64K × 8. (b) The chip has 16 address lines since 216= 64K.

How many address lines are required for addressing 2048 bytes of memory?

It means that a memory of 2048 words, where each word is 4 bits. So to address 2048 (or 2K, where K means 2^10 or 1024), you need 11 bits, so 11 address lines.

How many address bit are required for a 2048 bit memory organized as a 256 * 8 memory?

How many 256×8 RAM chips are needed to provide a memory capacity of 2048 bytes? Each RAM chip has 64 x 1 byte = 64 bytes. Thus the number of chips to address a memory capacity of 2048 bytes will be, 2048/64 = 32 chips.

How many address lines are needed for memory?

If n=2, you can address 2 locations (0, 1, 2, and 3). As you can see, number of addressable locations = n^2. This means that n=log(1024) to the base 2. Thus, n=10.

How many address line bits are required to access all locations in a 2048 8 memory?

How many 256 8 RAM chips are needed to provide a memory capacity of 2048 words?

How many 128k 16 RAM chips are needed to provide a memory capacity of 2 MB?

1 Approved Answer 16 groups of 8 chips which have same address/chip select lines.

How many address lines are required for 2MB memory?

Answer: It requires 21 address lines to address two megabytes of memory.

How many address lines are there in 64 KB?

Sixteen address lines will address 64K bytes. If you count in binary (which computers always do) and limit yourself to 16 binary columns, you can count from 0 to 65,535. (The colloquial ”64K” is shorthand for the number 66,536.)

How many address lines are needed for 2048 memory?

Address bus lines operate as binary numeral system so to address 2048 memory locations (here bytes) we need the same number of address lines as we need bits for representing number 2048 – that is 11. Since one chip has 128 bytes, to address them we need 7 address lines (128 = 2^7). These 7 address lines are common to all the chips.

How many address lines do you need for 16 chips?

Since we have 16 chips, we need 4 (2^4 = 16) address lines decoded to select the right chip. Quick check up: 4 lines to address chips + 7 address lines to address 128 bytes = 11 address lines all together.

How many address lines are necessary to access 64K x 8 memory system?

It does not matter what size the memory chips are. If the memory system is 64K x 8, then you need 16 address lines to access it. Perhaps you meant to ask how many address lines per chip. If so, there would be 8 chips and you would use 3 address lines to select which chip, with the remaining 13 address lines being common to all 8 chips.

How many address bits in a memory chip?

That depends on the memory architecture of the system. if the memory chips are byte wide and not used to create a multibyte bus, 11 address bits are needed. if the memory chips are 32 bits wide, 9 address bits are needed (with the CPU internally selecting which of the 4 bytes it will use).

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